第1个回答 2011-05-08
每相电抗 Z相= (R²+Xl²)½ = (8²+6²)½ = 10(Ω) Cosφ=R相/Z相=8/10=0.8
接成星形时,I线=I相=U相/Z相=220/10=22(A)
S=3I相U相=3*22*220=14.52(KVA) P=S*Cosφ = 14.52*0.8 = 11.616(KW)
接成三角形时, U相=U线=380V
故 I相= U相/Z相= 380/10 = 38(A) I线=3½I相=1.732*38 = 65.816(A)
S = 3I相U相= 3*38*380 = 43.32(KVA) P = S*Cosφ = 43.32*0.8 = 34.656(KW)本回答被提问者采纳