matlab矩阵赋值问题

Question

for t=1:k
for i=1+2^t:2^(k+1)+m-2^t
for j=1+2^t:2^(k+1)+m-2^t
BM(i,j)=max([BM1(i-2^(t-1),j-2^(t-1)),BM1(i-2^(t-1),j+2^(t-1)),BM1(i+2^(t-1),j-2^(t-1)),BM1(i+2^(t-1),j+2^(t-1))]);%%当t=2时，把BM换成别的表达式的话，问题就解决了；
Bm(i,j)=min([Bm1(i-2^(t-1),j-2^(t-1)),Bm1(i-2^(t-1),j+2^(t-1)),Bm1(i+2^(t-1),j-2^(t-1)),Bm1(i+2^(t-1),j+2^(t-1))]);
end
end
BM1=BM;
Bm1=Bm;
end
这段程序里，我想的得到当t=k是的BM1，应该是跟t=1时的BM1不一样的，可是程序结果显示一样，怎么回事 啊，应该怎么改？这里k是一个常数，t=1时，循环里的BM1也是已知的；

Answer 1

%以下程序已做修改，t=k时就是BM1{k}，Bm1{k}
for t=1:k
for i=1+2^t:2^(k+1)+m-2^t
for j=1+2^t:2^(k+1)+m-2^t
BM(i,j)=max([BM1(i-2^(t-1),j-2^(t-1)),BM1(i-2^(t-1),j+2^(t-1)),BM1(i+2^(t-1),j-2^(t-1)),BM1(i+2^(t-1),j+2^(t-1))]);%%当t=2时，把BM换成别的表达式的话，问题就解决了；
Bm(i,j)=min([Bm1(i-2^(t-1),j-2^(t-1)),Bm1(i-2^(t-1),j+2^(t-1)),Bm1(i+2^(t-1),j-2^(t-1)),Bm1(i+2^(t-1),j+2^(t-1))]);
end
end
BM1{t}=BM;
Bm1{t}=Bm;
end追问

BM(i,j)=max([BM1(i-2^(t-1),j-2^(t-1)),BM1(i-2^(t-1),j+2^(t-1)),BM1(i+2^(t-1),j-2^(t-1)),BM1(i+2^(t-1),j+2^(t-1))]),这里边的BM1也的变化呢呀

追答

不好意思，刚才没看清楚你的循环体里面也有BM1，你要求的t=k时的BM1和Bm1，只需要在源程序后面加上两句代码如下：
for t=1:k
for i=1+2^t:2^(k+1)+m-2^t
for j=1+2^t:2^(k+1)+m-2^t
BM(i,j)=max([BM1(i-2^(t-1),j-2^(t-1)),BM1(i-2^(t-1),j+2^(t-1)),BM1(i+2^(t-1),j-2^(t-1)),BM1(i+2^(t-1),j+2^(t-1))]);%%当t=2时，把BM换成别的表达式的话，问题就解决了；
Bm(i,j)=min([Bm1(i-2^(t-1),j-2^(t-1)),Bm1(i-2^(t-1),j+2^(t-1)),Bm1(i+2^(t-1),j-2^(t-1)),Bm1(i+2^(t-1),j+2^(t-1))]);
end
end
BM1=BM;
Bm1=Bm;
end
BM1
Bm1
%直接在command窗口可以看到你要的BM1和Bm1

追问

还是不对啊，再帮忙看看啊

追答

你把整个程序补充完整，我再帮你看看。