C++读取一行数据(每个数据用空格隔开)导入数组中

Question

一个number.txt文件里面的内容如下：
1 2 3 4 5 6 7 8 9 0

ifstream infile;
infile.open("number.txt");
if (infile.fail())
{
cout << "Error! File does not exist." << endl;
return 1;
}
string x[10];

for (int i= 0; i < 10; i++)
getline(infile, x[i]);

for (int i = 0; i < 10; i++)
{
cout << x[i];
}
结果的确是打印出了1 2 3.。。。。0
但是这里x[0]就等于1 2 3 4 5 6 7 8 9 0
我想要的是x[0]=1 x[1]=2.......x[9]=0

Answer 1

#include <iostream>
#include <vector>
#include <string>
#include <sstream>
using namespace std;

int main() {
string input;
getline(cin, input);
stringstream stringin(input);
int num;
vector<int> a;
while (stringin >> num) {
a.push_back(num);
}
for (int i = 0; i < a.size(); i++) {
cout << "a[" << i << "] = " << a[i] << " ";
}
cout << endl;
}本回答被提问者和网友采纳