function e=hundungen(M,N,key0)
for(i=1:200)
key0=3.925*key0*(1-key0);
end
key1=3.925;
for(i=1:M)
for(j=1:N)
key0=key1*key0*(1-key0);
a(i,j)=key0;
end
end
key3=0.2;
key2=3.925;
for(i=1:M)
for(j=1:N)
key3=key2*key3*(1-key3);
b(i,j)=key3;
end
end
key4=0.3;
key2=3.925;
for(i=1:M)
for(j=1:N)
key4=key2*key4*(1-key4);
c(i,j)=key4;
end
end
t=0.4;
w0=0.2;
w1=0.5;
w2=0.3;
w=(1-t)^2*w0+2*t*(1-t)*w1+t^2*w2;
for(i=1:M)
for(j=1:N)
P(i,j)=(1-t)^2*a(i,j)*w0+2*t*(1-t)*b(i,j)*w1+t^2*c(i,j)*w2;
% d(i,j)=P(i,j)/w;
d(i,j)=P(i,j);
end
end
x=d;
e=round(x*255);
end
你都不知道M、N 的值就知道答案了神啊
追答不信算了