求一个计算5x5矩阵中每个数出现的次数c语言代码，，谢谢

Question

如题所述

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
main()
{
int a[5][5],i,j,sum1=0,sum2=0;
srand()(time(NULL));
for(i=0;i<5;i++)
{
for(j=0;j<5;j++)
{
a[i][j]=rand()()%20+1;
if(i==j)
sum1+=a[i][j];
if((i+j)==4)
sum2+=a[i][j];
printf("%3d",a[i][j]);
}
printf("\n");
}
printf("对角线元素之和分别为:%d\t%d\n",sum1,sum2);
}