SQL查询：如表：消费记录有很多，如何得到每个人的最后一次的消费记录，

Question

假设表为T_ClientConsuemLog 字段包含：F_ClientConsumeID,F_ClientID,F_ClientConsumeDate,F_ClientConsumeMon

Answer 1

select top 1 * from T_ClientConsuemLog order by F_ClientConsumeMon desc ,F_ClientConsumeDate desc;追问

肯定不对

Answer 2

oracle

select F_ClientConsumeID,F_ClientID,F_ClientConsumeDate,F_ClientConsumeMon from (
select F_ClientConsumeID,F_ClientID,F_ClientConsumeDate,F_ClientConsumeMon, row_number() over(partition F_ClientConsumeID order by F_ClientConsumeDat desc) "row" ) where "row"=1

Answer 3

select count(* ) from T_ClientConsuemLog
select * from T_ClientConsuemLog
group by F_ClientConsumeID -- 不知道那个字段代表 人追问

F_ClientConsumeID,F_ClientID,F_ClientConsumeDate,F_ClientConsumeMon 分别是消费序号；客户编号，消费时间，消费金额

Answer 4

是同一个F_ClientID有很多条把？
select * from T_ClientConsuemLog,(
select max(F_ClientConsumeID) as fid from T_ClientConsuemLog group by F_ClientID) tablea
where T_ClientConsuemLog. F_ClientConsumeID = tablea.fid本回答被提问者和网友采纳