第1个回答 2012-10-10
1. X和y是自然数,规定小x*y=4X-3y,如果5*a=8,那么a是几?
a=(4*5-8)/3
=4
2. 某班一次集合,请假人数是出席人数的1/9,中途又有一人请假离开,这样一来请假人是出席人数的3/22,那么这个班共有多少人?
解:设第一次请假人为X,则出席人数为9X
(9X-1)*(3/22)=x+1
x=5
所以:总人数为5+9*5=50(人)
3. 8又4分之3-0.35+(1又4分之1-6又20分之13)
解:=8又3/4-7/20+1又1/4-6又13/20
=(8又3/4+1又1/4)-(7/20-6又13/20)
=3
4. 1/2*3 +1/3*4 +1/4*5......+1/49*50
=1/2-1/3+1/3-1/4+1/4-1/5+......+1/49-1/50
=1/2-1/50
=12/25
5. 1/1*3+1/3*5+1/5*7+......+1/47*49
=(1-1/3+1/3-1/5+1/5-1/7+.......+1/47-1/49)*1/2
=(1-1/49)*1/2
=48/49*1/2
=24/49
6. 1/2*5+1/5*8+1/8*11+......+1/20*23
=(1/2-1/5+1/5-1/8+1/8-1/11+......+1/20-1/23)*1/3
=(1/2-1/23)*1/3
=21/46*1/3
=7/46
7. 1又13+7/12-9/20+11/30-13/42
=1又1/3+1/3+1/4-1/4-1/5+1/5+1/6-1/6-1/7
=1又2/3-1/7
=1又11/21
8. 2003/1*3+2002/3*5+2002/5*7+2002/7*9+2002/9*11
=(1/1*3 *2002 +1/3*5 *2002 +1/5*7 *2002 +1/9*11 *2002)*1/2
=(1-1/3+1/3-1/5+1/5-1/7+1/9-1/11)*2002*1/2
=(1-1/11)*2002*1/2
=10/11*2002/2
=910
9. 1/2+1/4+1/8+1/16+1/32
=(1/2+1/4+1/8+1/16+1/32+1/32)-1/32
=1-1/32
=31/32
10. 1/12+1/20+1/30+1/42+1/56+1/72+1/90
=1/3-1/4+1/4-1/5+1/5-1/6.....+1/9-1/10
=1/3-1/10
=7/30
11. 1-1/4+1/20+1/30+1/42+1/56
=1-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8
=1-1/8
=7/8
12. 1/1*5+1/5*9+1/9*13+......+1/55*59
=(1-1/5+1/5-1/9+1/9-1/13+......+1/55-1/59)*1/4
=(1-1/59)*1/4
=29/118
13 . (1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)+(1/3+1/5+1/7)
设(1+1/3+1/5+1/7)为a,(1/3+1/5+1/7)为b
a*(b+1/9)-(a+1/9)*b
=ab+1/9a-ab-1/9b
=1/9*(a+b)
=1/9
14. 5/14*5/6-7/12*5/14+9/20*5/14
=5/14*(5/6-7/12+9/20)
=5/14*[1/2+1/3-(1/3+1/4)+1/4+1/5]
=5/14* (1/2+1/3-1/3-1/4+1/4+1/5)
=5/14*7/10
=1/4
15. 1/3+1/15+1/35+1/63+1/99
=1/1*3 +1/3*5 +1/5*7 +1/7*9 +1/9*11
=(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11)*1/2
=(1-1/11)*1/2
=5/11
没有时间了,以后再帮助你。本回答被提问者和网友采纳