第1个回答 2018-03-19
double average(double &max, double &min, double a[], int num){
double sum = 0;
for(int i = 0; i < num; i++){
if(i==0){max=a[0]; min=a[0];}
else if(max<a[i] || min>a[i]){
if(max<a[i]) max=a[i];
if(min>a[i]) min=a[i];
}
sum+=a[i];
}
return (sum/num);
}本回答被网友采纳