如题所述
X~B(2,0.4)
P(X=0) = (0.6)^2 =0.36
P(X=1)=(2C1)(0.4)(0.6) =0.48
P(X=2) = (0.4)^2 = 0.116
分布函数
F(X)
=0.36 ; x<1
=0.84 ; 1≤x<2
=1 ; x>2