第1个回答 2017-09-27
图结构尺寸全L=2.5m,h=2m图未标.A'A"D属二力杆类型,A'A"=A"D=L,A'D连线与水平向夹角45度|FDx|=|FDy|……①.(1)取DB"B'隔离体:ΣMB'(F)=0|FDx|.L+|FDy|.L-F.L=0①代入式:|FDx|=|FDy|=F/2ΣFx=0,-|FB'x|+F-F/2=0|FB'x|=F/2=5kNΣFy=0.|FB'y|-|FDy|=0|FB'y|=|FDy|=F/2=5kN.(2)取二力杆A'A"D隔离体用类似求:|FA'x|=|FDx|=F/2=5kN|FA'y|=|FDy|=F/2=5kN……②.(3)取结构整体受力析象:ΣMB(F)=0FAy.2L-F.2L=0F值代入式:FAy=10kN(向)……③.(4)取AA'C隔离体:ΣMC(F)=0,FAy.L+FAx.L+|FA'y|.L=0②、③代入式:(10kN).L-FAx.L+(5kN).L=0FAx=15kN(向左)
-本回答被提问者采纳