已知F1=10KN,F2=5KN,求A,B处支座反力

Question

如题所述

Answer 1

ΣMA =0, FB.3(lm) +F1.2(lm) -F2.1(lm) =0
FB.3 +10KN.2 -5KN.1 =0
FB = -5KN（向下）
.
ΣMB =0， -FAy.3(lm)+F2.2(lm) -F1.1(lm) =0
-FAy.3 +5KN.2 -10KN.1 =0
FAy =0
.
ΣFx =0, FAx =0本回答被网友采纳