第1个回答 2008-06-03
#include <stdio.h>
#include <stdlib.h>
int main()
{
int one,two,five,num=0;
for(one=0;one<=100;one++)
for(two=0;two<=50;two++)
for(five=0;five<=20;five++)
if(one+two*2+five*5==100){num++;
printf("100=%d*1+%d*2+%d*5\n",one,two,five);}
printf("\n%d possibilities\n",num);
system("pause");
return 0;
}本回答被提问者采纳