C语言:输入年月日,判断为该年的第几天答:include "stdio.h"void main(){ int day,month,year,sum,leap;printf("\nplease input year,month,day\n ");scanf("%d%d%d",&year,&month,&day);//这句输入。注意格式就行 switch(month){ case 1:sum=0;break;case 2:sum=31;break;case 3:sum=59;break;case 4:sum=90;break;case...
C语言题:给出年月日,用函数计算是该年的第几天答:include "stdio.h"int main(int argc,char *argv[]){int y,m,d,w[12]={31,28,31,30,31,30,31,31,30,31,30,31},day,i;printf("Please enter the year, month and day(format: yyyy-m-d)...\n");scanf("%4d-%2d-%2d",&y,&m,&d);if(y>0 && m>0 && m<13 && d>...
输入日期(年,月,日),输出它是该年的第几天答:include<stdio.h>int day_of_year(int year,int month,int day){//函数不能嵌套定义 int k,leap; int tab[2][13]={ {0,31,28,31,30,31,30,31,31,30,31,30,31},///少逗号 {0,31,29,31,30,31,30,31,31,30,31,30,31} }; leap=(year%4==0&&year%100!=0||year%400=...
怎么用C语言输入一个日期,求该日期是该年的第几天?答:我大概给个思路,代码是现写的 没调试先定义每个月的天数,2月按28天算输入年月日后,根据年判断是否闰年(闰年加1天),再从1月加到当月的前一月,再加上日期就可以了#include <stdio.h>int month[12] = {31,28,31,30,31,30,31,31,30,31,30,31};main(){int yy,mm,dd, days;int ...