运筹学问题 求解。。答:设每个班次上班的人数为:x1,x2,x3,x4,x5,x6 目标函数min(sum(x1,x2,x3,x4,x5,x6))限制条件 x1,x2,x3,x4,x5,x6>=0,x1,x2,x3,x4,x5,x6为整数 x6+x1>=60 x1+x2>=70 x2+x3>=60 x3+x4>=50 x4+x5>=20 x5+x6>=30 (31,39,21,29,1,29),150 ...
运筹学问题答:8x1+x2-4x3=2x5=10 这个约束有问题 应该为8x1+x2-4x3+2x5=10 对不对,如果是的话,所有基解为:X1=(0,16/3,-7/6,0,0)X2=(0,10,0,-7,0,0) X3=(0,3,0,0,7/3,0) X4=(7/4,-4,0,0,0,21/4) X5=0,16/3,-7/6,0,0,0)X6=0,10,0,-7,0,0) X7=...