鸡兔同笼,其中共有25个头,80个脚,问鸡笼里有鸡和兔各多少只,用c语言编 ...答:include <stdio.h>int main(){ int tou=25,i,tuzi[10],count=0; for(i=1;i<=tou;i++) { printf("假设兔子%d只,鸡%d只,那么兔脚%d个,鸡脚%d个",i,tou-i,i*4,(25-i)*2); if(i*4+(25-i)*2==80) { tuzi[count++]=i; printf("与总数80相符...
编程 鸡兔同笼问题。已知鸡和兔的总数量,鸡腿和兔腿的总数量,求鸡和...答:假设有head个头和foot只脚 程序如下:include<stdio.h> void main(){int i,head,foot,rabbit,chick;printf("Enter the 2 numbers :");scanf("%d%d",&head,&foot);printf("head=%d,foot=%d\n",head,foot);for(i=0;i<=head;i++){rabbit=i;chick=head-rabbit;if(rabbit*4+chick*2==...