C语言编程,求一个人的年龄是多少。答:%d,%d",&y0,&m0,&d0);printf("请输入当前日期:");scanf("%d,%d,%d",&y1,&m1,&d1);nianling=y1-y0;if(m1>m0){if(d1>d0)nianling--;printf("%d",nianling);}elseprintf("%d",
c语言问题,张三,李四,王五,刘六的年龄为一等差数列,他们四人年龄相加是...答:下面依次从1到sum/4,开始试验等差,如果是则,sum-6y必能被4整除,如果能整除 再看它们的积是否是muti,是则为正解。输出即可。include "stdio.h"void main(){ int i,j,k=0,sum,muti;printf("please enter sum:");scanf("%d",&sum);printf("please enter muti:");scanf("%d",&muti)...
C语言编程10名同学,求出年龄最大,最小,平均年龄答:double sum,max,min,a;int i;int main() { max=0;min=1e99;sum=0;for (i=0;i<10;i++) { scanf("%lf",&a);if (a>max) max=a;if (a<min) min=a;sum+=a;} printf("最大:%lf\n",max);printf("最小:%lf\n",min);printf("平均:%lf\n",sum/10);return 0;} ...