C语言:输入精度e 和实数x,用下列公式求cos x 的近似值,精确到最后一项...答:double funcos(double x,double e);int main(void){ double n,x,e;scanf("e: %lf%*c",&e);scanf("x: %lf%*c",&x);n=funcos(x,e);printf("cos(x)=%.3lf",n);return 0;} double funcos(double x,double e){ int i,k,flag=1;double sum,result=0,fact=1;for(i=0;...