已知向量a=(8,2),b=(3,3),c=(6,12),p=(6,4),问是否存在实数x,y,z...答:=> 6 = 8x+3y+6z 4 = 2x+3y+12z x=0, y= 8/3, z= -1/3 satisfy the above equations.存在实数x,y,z满足下列条件 (2)x+y+z=1 8x+3y+6z = 6 (1)2x+3y+12z = 4 (2)x+y+z=1 (3)(1)-(2)6x-6z=2 3x-3z=1 (4)3*(3)-(1)x-9z=-1 (5...