python编程求Fibonacci数列的前30项。答:diGui(n, c, result, temp):if c != 1:temp = result - temp result += temp if n == 1:return str(result)return str(result) + ' , ' + diGui(n - 1, c + 1, result, temp)print("斐波那契数列到第{}个的结果是:1 , {}".format(30, diGui(29, 1, 1, 0)))
python :用for循环求斐波那契答:①填:in range(3, n + 1):②填:a, b = b, a + b 完整代码为:n = int(input('请输入n: '))a = b = 1 print(1, 1, end = '')for x in range(3, n + 1):print('', a + b, end = '')a, b = b, a + b 运行结果为:如图输出了斐波那契数列的前10项,...