python 列表中嵌套元组的提取答:index={'合作':[(0, 5)], '每次':[(20, 99), (30, 11), (31, 69), (31, 80)],'在意':[(6, 40), (9, 5)]}for key in index:print('--- ',key,' ---')for i in range(len(index[key])):print(index[key][i]...
python2.7中列表和元组间的转化,如何将一个包含元组的列表变成一个列表...答:aaa=[[('s1',)], [('s1',)], [('s1',)], [('s1', 's2')], [('s1', 's2')], [('s1', 's2')], [('s1', 's2')]]bbb=[]for each in aaa: for ec in each: bbb.append(list(ec))